请问在x86 linux2.4下，系统对pci板卡的base_address[]是如何配置的？

base_address[0]、base_address[1]、base_address[2]....中各存的是什么？这些内容是由谁来分配的？
非常感谢！

由系统分配的，存的就是pci configuration space中的base address.

那就是说是linux自动分配的？那么pci configure space 中IO /memory等的分配各自分配到了 base_address[0]还是base_address[1]还是....?谢谢！

系统会读取每个base_address[]的值来判断该寄存器存放的是IO空间或memory空间，Bit0 of all base address registers 决定寄存器是映射到IO 或Memory， （bit0==0  IO,  bit0==1 memory）。

具体实现是读取该寄存器的值，然后写回0xFFFFFFFF，再读回该寄存器值，如果第二次读回的值不为全0或全1，则该base address register包含地址映射值,具体linux实现代码如下 :
for(pos=0; pos<6; pos = next) {
next = pos+1;
res = &dev->resource[pos];
res->name = dev->name;
reg = PCI_BASE_ADDRESS_0 + (pos << 2);
pci_read_config_dword(dev, reg, &l);
pci_write_config_dword(dev, reg, ~0);
pci_read_config_dword(dev, reg, &sz);
pci_write_config_dword(dev, reg, l);
if (!sz || sz == 0xffffffff)
continue;
if (l == 0xffffffff)
l = 0;
if ((l & PCI_BASE_ADDRESS_SPACE) == PCI_BASE_ADDRESS_SPACE_MEMORY) {
res->start = l & PCI_BASE_ADDRESS_MEM_MASK;
sz = pci_size(sz, PCI_BASE_ADDRESS_MEM_MASK);
} else {
res->start = l & PCI_BASE_ADDRESS_IO_MASK;
sz = pci_size(sz, PCI_BASE_ADDRESS_IO_MASK & 0xffff);
}
res->end = res->start + (unsigned long) sz;
res->flags |= (l & 0xf) | pci_calc_resource_flags(l);
if ((l & (PCI_BASE_ADDRESS_SPACE | PCI_BASE_ADDRESS_MEM_TYPE_MASK))
   == (PCI_BASE_ADDRESS_SPACE_MEMORY | PCI_BASE_ADDRESS_MEM_TYPE_64)) {
pci_read_config_dword(dev, reg+4, &l);
next++;
#if BITS_PER_LONG == 64
res->start |= ((unsigned long) l) << 32;
res->end = res->start + sz;
pci_write_config_dword(dev, reg+4, ~0);
pci_read_config_dword(dev, reg+4, &sz);
pci_write_config_dword(dev, reg+4, l);
if (~sz)
res->end = res->start + 0xffffffff +
(((unsigned long) ~sz) << 32);
#else
if (l) {
printk(KERN_ERR \"PCI: Unable to handle 64-bit address for device %s\\n\", dev->slot_name);
res->start = 0;
res->flags = 0;
continue;
}
#endif
}
}

谢谢！我是想知道系统对于每一个base_address[]是怎么分配的？每一个base_address[]中分配的是什么东东？
谢谢您的回答！