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阅读：1102回复：4
memcpy
// stick unsigned long count at the beginning of buffer
memcpy(threadParam->pcIoBuffer + index*64, &seq, min(sizeof(ulCount), threadParam->uiLength)); 什么意思 |
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沙发#
发布于：2004-02-04 10:41
你想问什么
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板凳#
发布于：2004-02-04 10:56
memcpy这个函数的功能
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地板#
发布于：2004-02-07 14:20
是不是你发邮件给我？
我回复你的地址总是被退回来！ 以下是内容： y_xun,您好！ 拷贝的时候用如下方法： RtlCopyMemory((char *)pMdlAddress, ioBuffer, 1024);//最后一个参数是数量。以字节为单位。 |
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地下室#
发布于：2004-02-08 03:33
SYNOPSIS
#include <string.h> void *memcpy(void *s1, const void *s2, size_t n); DESCRIPTION The memcpy() function operates as efficiently as possible on memory areas. It does not check for overflow of any receiving memory area. Specifically, memcpy() copies n bytes from memory area s2 to s1. It returns s1. PARAMETERS s1 Points to the target buffer. s2 Points to the source buffer n Is the number of bytes to copy. |
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